Question

A wire whose area 2mm^2 is stretched by a 1mm by a certain load if a similar wire is tripled in area is stretched by the same load elongation here would be?

Answer 1

Answer:

1/3 mm

Explanation:

E = stress/strain = F/A ÷ ΔL/L

F2/A2 ÷ ΔL2/L2  = F1/A1 ÷ ΔL1/L1  , F2 = F1 , L2 = L1

then

1/A2 ÷ ΔL2 = 1/A1 ÷ ΔL1

ΔL2A2 =  ΔL1A1

ΔL2 =  ΔL1A1/A2 = ΔL1A1/3A1 = ΔL1/3 = 1/3 mm