A wire whose area 2mm^2 is stretched by a 1mm by a certain load if a similar wire is tripled in area is stretched by the same load elongation here would be?
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Answer:
1/3 mm
Explanation:
E = stress/strain = F/A ÷ ΔL/L
F2/A2 ÷ ΔL2/L2 = F1/A1 ÷ ΔL1/L1 , F2 = F1 , L2 = L1
then
1/A2 ÷ ΔL2 = 1/A1 ÷ ΔL1
ΔL2A2 = ΔL1A1
ΔL2 = ΔL1A1/A2 = ΔL1A1/3A1 = ΔL1/3 = 1/3 mm
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