A wire whose resistance is 80Ω is cut into three pieces of equal lengths which are then arranged in parallel. Calculate the resistance of the combination.
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The resistance of each piece of wire will be80/3
When they r added in parallels then
3/80+3/80+3/80=1/R
R=80/9
R=8.8ohm
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2
Answer:
Explanation:
if the length becomes L/3 the resistance also becomes R/3. Thus, the resistance of each piece is 80/3 ohm. Now, we have three such pieces connected in parallel. The equivalent resistance of the combination is,
1/R eq = 1/(80/3) + 1/(80/3) + 1/(80/3)
=> 1/R eq = 9/80
=> R eq = 80/9 = 8.88 ohm
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