Question

A wodden cylinder of length 14 cm has a diameter 8 cm what is the volume of cylinder​

Answer 1

Answer:

V≈703.72cm³

d Diameter

8

cm

h Height

14

cm

Answer 2

$\maltese\LARGE\textsf{\underline{ GiVeN :-}}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\large\textsf{Height of the cylinder ( h ) = 14 cm}$

$\qquad\tt{:}\longrightarrow\large\textsf{Diameter of the cylinder ( d ) = 8cm}$

$\large\textsf{ }$

$\maltese\LARGE\textsf{\underline{ To FiNd :-}}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\large\textsf{Volume of the cylinder = ?}$

$\large\textsf{ }$

$\maltese\LARGE\textsf{\underline{ FoRmUla :-}}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\boxed{\large\textsf\textcolor{purple}{ {\large\textsf\textcolor{purple}{Volume}}_{\large\textsf{( \; Cylinder \; )}} = \large\textsf{πr²h} }}$

$\large\textsf{ }$

$\maltese\LARGE\textsf{\underline{ SoLuTioN :-}}$

$\large\textsf{ }$

↦ We know that :-

$\qquad\tt{:}\longrightarrow\large \sf \: r \: \: = \: \: \frac{d}{2} \\ \\\qquad\tt{:}\longrightarrow\large \sf r \: \: \: = \: \: \frac{8}{2} \\ \\ \\ \therefore\large \sf \boxed{\sf\: \: r \: \: \: = \: \: \: 4 \: \: cm }$

$\qquad\tt{:}\longrightarrow\large\sf \: volume \: \: \: \: of \: \: \: \: the \: \: \: \: cylinder \: \: \: = \: \: \: \pi {r}^{2} h \\ \\ \\ \qquad\tt{:}\longrightarrow\large \sf\: \: \: \frac{22}{ \cancel7} \: \: \times \: \: 4 \: \: \times \: \: 4\: \: \times \: \: \cancel{14} \\ \\ \\ \qquad\tt{:}\longrightarrow\large \sf \: \: 22 \: \: \times 4 \: \: \times \: \: 4 \: \: \times \: \: 2 \\ \\ \\ \qquad\tt{:}\longrightarrow\large \sf = \boxed{ \sf \color{red}704\: \: \: {cm}^{3} }$

$\large\textsf{ }$

$\maltese\LARGE\textsf{\underline{ MoRe fOrMuLaS :-}}$

$\large\textsf{ }$

$\large\textsf{ {\large\textsf{L.S.A.}}_{\large\textsf{( \; Cuboid \; )}} = \large\textsf{2h ( l + b )} }$

$\large\textsf{ {\large\textsf{T.S.A.}}_{\large\textsf{( \; Cuboid \; )}} = \large\textsf{2 ( lb + bh + hl )} }$

$\large\textsf{ {\large\textsf{Volume}}_{\large\textsf{( \; Cuboid \; )}} = \large\textsf{l×b×h} }$

$\large\textsf{ }$

$\large\textsf{ {\large\textsf{L.S.A.}}_{\large\textsf{( \; Cube \; )}} = \large\textsf{4×l²} }$

$\large\textsf{ {\large\textsf{T.S.A.}}_{\large\textsf{( \; Cube \; )}} = \large\textsf{6 × l²} }$

$\large\textsf{ {\large\textsf{Volume}}_{\large\textsf{( \; Cube \; )}} = \large\textsf{l²} }$

$\large\textsf{ }$

$\large\textsf{ {\large\textsf{C.S.A.}}_{\large\textsf{( \; Cylinder \; )}} = \large\textsf{2 × πrh} }$

$\large\textsf{ {\large\textsf{T.S.A.}}_{\large\textsf{( \; Cylinder \; )}} = \large\textsf{2πr × ( r + h )} }$

$\large\textsf{ {\large\textsf{Volume}}_{\large\textsf{( \; Cylinder \; )}} = \large\textsf{πr²h} }$

$\large\textsf{ }$

$\large\textsf{ {\large\textsf{C.S.A.}}_{\large\textsf{( \; Cone \; )}} = \large\textsf{πrl} }$

$\large\textsf{ {\large\textsf{T.S.A.}}_{\large\textsf{( \; Cone \; )}} = \large\textsf{πr × ( r + l )} }$

$\large\textsf{ {\large\textsf{Volume}}_{\large\textsf{( \; Cone \; )}} } \large\textsf{ = \cfrac{\large\textsf{1}}{\large\textsf{3}} }\large\textsf{× πr²h}$

$\large\textsf{ }$

$\large\textsf{ {\large\textsf{T.S.A.}}_{\large\textsf{( \; Sphere \; )}} = \large\textsf{4πr²} }$

$\large\textsf{ {\large\textsf{Volume}}_{\large\textsf{( \; Sphere \; )}} } \large\textsf{ = \cfrac{\large\textsf{4}}{\large\textsf{3}} }\large\textsf{× πr³}$

$\large\textsf{ }$