Physics, asked by ifunanyae523, 24 days ago

A woman at mass 80kg lifts a bricks of mass 20kg up a vertical ladder of width 2m width length 6m. What is the work done?



Answers

Answered by Mankuthemonkey01
20

Here we'll assume that the woman lifted the brick slowly.

That'd mean that she applied a force just equal to the gravitational force acting on the brick.

Gravitational force by earth acting on an object is given by

F = mg

where, m is the mass of object and g is the acceleration due to gravity (which is equal to 9.8 ms-²)

Here, mass of brick is 20 kg

So force by gravity (Fg) would be

Fg = 20 × 9.8 = 196N (unit of force is Newton, N)

Now the woman would apply the same force upwards

Fw = 196 N (upwards)

Fw is the force applied by woman.

Now work done is equal to Force × displacement

Here, Force = Fw = 196 N

displacement = 6 m

So work done by woman = 196 × 6

= 1176 N

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