Question

a woman has a certain humber of mangos of which 13% are rotten she gives 75% of the remainder in charity and then has 261 left how money had she at first.

Answer 1

total number of mangoes at first be x
no. of rotten mangoes = 13x/100
mangoes left = 87x/100
mangoes given to charity = 75% of 87x/100 = 6525x/10000
so, mangoes left = 87x/100 - 6525x/10000 = 2175x/10000
by the given condition, 2175x/10000 = 261
by solving we get, x = 1200
The answer is 1200.
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Answer 2

let the total no of mangoes at first be x
so rotten mangoes =13x/100
remainder=87x/100
mangoes given to charity =6525x/10000
so mangoes left=87 x/100 _6525x/10000
=2175 x/10000
so 2175 x/10000 =261
=>x=1200
so she had 1200 mangoes atfirst.