Math, asked by nilimasaha208, 7 months ago

A woman has a certain number of mangoes of which 13% are rotten get 75% of the remainder ina charity and then had 261 left how many had​

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Answered by shrutinemane1
3

Answer:

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Let the total number of mangoes be x

13 % are rotten = 13 × x/100 = 0.13x

Remaining mangoes = x - 0.13x = 0.87x

75 % 0f remaining mangoes given in charity = 75 × 0.87x/100

= 0.6525x

Therefore we know that,

total number of mangoes = 13 % are rotten + 75 % of the remaining given in charity + number of mangoes left

⇒ x = 0.13x + 0.6525x + 261

⇒ x = 0.7825x + 261

⇒ x - 0.7825x = 261

⇒ 0.2175x = 261

⇒ x = 261/0.2175

total number of mangoes = 1200

Step-by-step explanation:

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