Question

a woman has only 50-paisa and 1-rupee coin in her purse if in all she has 70 coins totalling rupees 45 how many coins of 50 she has

Answer 1

$\boxed{\bold{\large{Answer:}}}$

$\text{Let\:50\:paisa\:Coins\:be\:x\:=\:50x}$

$\text{So,\:The\:70\:rupee\:Coins\:will\:be\:70\:-\:x\:=\:100(70\:-\:x)...... (i)}$

$\text{45\:rupees\:will\:be\:equal\:to\:4500\:Paisa......(ii)}$

$\text{From\:(i)\:and\:(ii)\:we\:get,}$

⇒ 50x + 100(70-x) = 4500

⇒ 50x + 7000 - 100x = 4500

⇒ -50x = -2500

⇒ x = 50

$\text{She\:has\:50\:coins\:of\:50\:Paisa}$

$\boxed{\bold{\large{Hope\:it\:helps\:you!}}}$

Answer 2

HEY MATE HERE IS YOUR ANSWER

$\rule {144} {4}$

Given :-

a woman has only 50 paise and one rupee coin in her purse and has 70 coins total rupees 45.

Let 50 paise coins be x.

So,

70 ₹ coins will be 70 - x = 100(70-x) - - - - (1)

45 coins will have 4500 paise - - - - - (2)

$\rule {135}{2}$

From equations 1 and 2 we get,


➡️ 50x + 100(70 - x) = 4500

➡️ 50x + 7000 - 100x = 4500

➡️ 50x - 100x = 4500 - 7000

➡️ - 50x = - 2500

➖from ➖ will be cut

➡️ 50x = 2500

➡️ x = 50

Therefore,

She have 50 coins of 50 paise

__________________________

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