A woman has RS 1000 with her . She calculated that she could spend RS x every day on her holiday she spent RS x-50 every day and extended her holiday by 10 days calculate x ?
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Let the days be 'y'
Money spent every day = x
ATQ
1000/x = y
1000 = xy eq.1
y = 1000/x. eq.2
1000/(x-50) = y+10
1000 = (x-50)(y+10)
1000 = xy + 10x -50y - 500
1000 = 1000 + 10x - 50y - 500
0 = 10x - 50y - 500
500 = 10x - 50y
50 = x - 5 y
50 = x - 5(1000/x)
50 = x - 5000/x
50 = (x^2 - 5000) / x
50x = x^2 - 5000
x^2 - 50x - 5000 = 0
x^2 - 100x + 50x - 5000 = 0
x(x-100) + 50(x-100) = 0
(x+50)(x-100) = 0
x = -50
x = 100
Money cannot be negative so x = 100
Money spent every day = x
ATQ
1000/x = y
1000 = xy eq.1
y = 1000/x. eq.2
1000/(x-50) = y+10
1000 = (x-50)(y+10)
1000 = xy + 10x -50y - 500
1000 = 1000 + 10x - 50y - 500
0 = 10x - 50y - 500
500 = 10x - 50y
50 = x - 5 y
50 = x - 5(1000/x)
50 = x - 5000/x
50 = (x^2 - 5000) / x
50x = x^2 - 5000
x^2 - 50x - 5000 = 0
x^2 - 100x + 50x - 5000 = 0
x(x-100) + 50(x-100) = 0
(x+50)(x-100) = 0
x = -50
x = 100
Money cannot be negative so x = 100
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