Math, asked by ShrChhaya, 1 year ago

A woman invest 2000/- at the start of each year at 5% compound interest per annum.How much will her investment be at the end of the 2nd year

Answers

Answered by samruddhi8815
7

hey .........here's ur answer.......

given is

principal 2000rs.

rate 5 %

time 2 years

A is P×(1+R÷100)t(sq)

2000×(1+5÷100)2

2000×105÷100×105÷100

2×105×105

22050 rs

CI is A-P

22050-2000

20050

hope it helps u.......

mark it as brainiest.......✌️✌️

Answered by windyyork
0

The investment becomes Rs. 2205 at the end of 2nd year.

Step-by-step explanation:

Since we have given that

Sum = Rs. 2000

Rate of interest = 5%

Time = 2 years

So, Amount would be

A=P(1+\dfrac{r}{100})^n\\\\A=2000(1+\dfrac{5}{100})^2\\\\A=2000(1.05)^2\\\\A=2205

Hence, the investment becomes Rs. 2205 at the end of 2nd year.

# learn more:

You invested $4,500 in a project which gave you a return of 13.1% the 1st year. you were quite happy, but the 2nd year wasn't as good. you lost 4.3% that year. the 3rd year was better - you made 5.9% on this investment. what was your annual average rate of return over the three years?

https://brainly.com/question/10872943

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