Question

A woman is 4 times as old as her son.9 years ago,the sum of their ages was 42.Find their present ages

Answer 1

Step-by-step explanation:

Let the present ages of woman and her son be x and y years.

From first condition

x=4y...(1)

From second condition

(x-9)+(y-9)=42

x+y-18=42

x+y=42+18

x+y=60...(2)

substitute eq(1) in eq(2)

4y+y=60

5y=60

y=60/5

y=12.

But

x=4y

x=4(12)

x=48.

The present ages of woman and her son is 12 and 48 years respectively.