Question

A woman is 7 times as old as her son. After 5 years she will be 4 times as old as her son .what are the present ages of the mother and son

Answer 1

let the present age of son be x

present age of women = 7x

after five years,

7x+5 = 4(x+5)

7x+5 = 4x+20

3x = 15

x = 5

present age of son = 5

present age of women = 35

Answer 2

Answer:

let the present age of son be x

present age of women = 7x

after five years,

7x+5 = 4(x+5)

7x+5 = 4x+20

3x = 15

x = 5

present age of son = 5

present age of women = 35

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