Math, asked by 8002913394, 1 year ago

a woman is now 30 years older than her son .15 years ago, she was twice as old as her son. find the present age of the woman and her son

Answers

Answered by Anonymous
1
let the present age of son be x
and the present age of mother be y
y=x+30
x-y=-30
15 years ago,
son=x-15
mother=y-15
y-15=2(x-15)
y-15=2x-30
2x-y=15
therefore y=45 and x=15
son is 15 years old and mom is 45 years old
any doubt pls ask


Anonymous: plz ark as brainliest
8002913394: please solve in one variable
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