Question

a woman is now 30 years older than her son .15 years ago, she was twice as old as her son. find the present age of the woman and her son

Answer 1

Present age of woman = w = 75 years old
Present age of son = s = 45 years old

Present age of woman = w years old
Present age of son = s years old 
woman is now 30 years older than her son
w=s+30.........(1)
15 years ago
woman was = w-15 years old
son was = s-15 years old
Then
she was twice as old.
w-15=2(s-15)
w-15=2s-30

w=2s-30+15
w=2s-15...........(2)
Put the value of w from (1) to (2)
s+30=2s-15
s-2s=-15-30
-s=-45
s=45
Put the value of s in (1)
w=s+30.........(1)
w=45+30
w=75