Question

A woman is now 30 years older than her son. 15 years ago, she was twice as old as her son. Find the present age of the woman and her son now 30 years older than her son. 15 years ago, she was twice as old as her son. Find the present age of the woman and her son.

Answer 1

Step-by-step explanation:

Present age of woman = x years old

Present age of son = y years old 

woman is now 30 years older than her son

x=y+30.........(1)

15 years ago

woman was = x-15 years old

son was = y-15 years old

Then

she was twice as old.

x-15=2(y-15)

x-15=2y-30

x=2y-30+15

x=2y-15...........(2)

Put the value of x from (1) to (2)

y+30=2y-15

y-2y=-15-30

-y=-45

y=45

Put the value of y in (1)

x=s+30.........(1)

x=45+30

x=75 

Answer 2

Answer:

Step-by-step explanation:

let the son's age = x yrs

woman's age = x+30

15 years ago

son's age = x-15

woman's age = x+30-15 = x+15

2(x-15) = x+15

2x - 30 = x + 15

3x = 45

x = 15

son's age = 15 yrs

woman's age = 45 yrs