Math, asked by chdaniyalahmed, 10 months ago

A woman is now 8 times as old as her son mahd. Two years ago she was 15 times as old as mahd

A. If mahd is x year old now in term of x the women’s present age

B. Write down expression in terms of x for mahds age two year ago

C. From an equation in x and solve it

D. Find the woman’s age in 5 year time

Answers

Answered by b4bhist
6

Let present age of Mahd = x year

present age of woman = y year

As woman is now 8 times as old as her son

So, y = 8x .....................................equation 1

Two years ago she was 15 times as old as mahd

So,  y - 2 = 15 (x -2)

or  15x - y  = 28...............................equation 2

On Solving equation 1 & 2 we have

x = 4 year

y = 32 year

Answered by jaiswalrajesh709
0

The present age of Mahd = x year

The present age of woman = y year

The woman is now 8 times as old as he son

so, y=8x

Two years ago she was 15 times as old as mahds

So,  y - 2 = 15 (x -2)

or  15x - y  = 28...............................equation 2

x = 4 year

y = 32 year

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