Question

A woman is seven times as old as her son. After 5 years, she will be four times as old as her son. What are the present ages of the mother and son? ​

Answer 1

Step-by-step explanation:

Answer:

Mother's present age = 35 years.

Son's present age = 5 years.

Explanation:

Given,

A woman is seven times as old her son.

Let's say her son's present age \boldsymbol xx yrs.

∴ Women's present age = \boldsymbol {7x}7x yrs.

Now,

After 5 years she'll be 4 times the age of her son.

5 years later,

Mother's age = \boldsymbol {7x + 5}7x+5 yrs.

Son's age = \boldsymbol {x + 5}x+5 yrs.

According to the question,

\implies \: 7x + 5 = 4 \times (x + 5)⟹7x+5=4×(x+5)

Solving for \boldsymbol xx

\implies \: 7x + 5 = 4x + 20⟹7x+5=4x+20

\implies \: 7x - 4x= 20 - 5⟹7x−4x=20−5

\implies \: 3x= 15⟹3x=15

\implies \: x= \dfrac{15}{3}⟹x=

3

15

\therefore \boldsymbol{ x= 5}∴x=5

Hence,

Son's present age = \boldsymbol xx = 5 years.

Mother's present age = \boldsymbol {7x}7x = 35 years.

__________________________

it's

Answer 2

Answer:

refer to the attachment drop some thx plz