Question

A woman is seven times as old as her son. After 5 years, she will be four times as old as her son. What are the present ages of the mother and ​

Answer 1

Answer:

answer in the attachment

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Answer 2

Step-by-step explanation:

Let present age of daughter be x.

So 5 years ago her age =x−5

Her mother's age is 7(x−5)

Including 5 years from past to present and then to future =10

So 7x−35+10=3(x−5+10)

7x−25=3x+15

4x=40

x=10

so daughters age=10

mother's age=4×10=40.