A woman is wearing seatbelt while driving at 60 Km/Hour. She find it necessary to
slam on her brakes and she slows uniformly to stop in 1.6 s. What is the average
acceleration experienced by her.
Answers
Answer:
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Explanation:
V =0 , U = 60 KM\HR , time = 1.6 sec
So, a = v - u / t = - 60/ 1.6 = -30 km/ hr2
Given : A women is wearing her seat belt, while driving at 60km/hr.
She finds it necessary to slam on her brakes and she slows
uniformly to a stop in 1.6 sec.
To Find : the average acceleration experienced by her?
Solution:
u = 60 km/hr
= 60 * 1000 / 3600
= 50/3 m/s
a = ?
v = 0 as stops
t = 1.6 secs
v = u + at
=> 0 = 50/3 + a (1.6)
=> -50/3 = 1.6a
=> a = -50/(3 * 1.6)
=> a = - 50/4.8
=> a = -500/48
=> a = -125/12
=> a = -10.4167 m/s²
Finding in km/hr²
u = 60
v = 0
t = 1.6 secs = 1.6/3600 hr
0 = 60 + a ( 1.6/3600)
=> a (1.6/3600) = - 60
=> a = -60 * 3600 /1.6
=> a = 135000 km/hr²
=> a = 1.35 * 10⁵ km/hr²
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