Question

a woman pushes a lawn roller with a force of 180 Newton and the angle of 24 degree downwards from horizontal. to push a roller a horizontal distance of 50 metre she has to do the work of? ​

Answer 1

Solution

To find the work done by the woman in pushing the trolley

We know that,

W = Fs.cos∅

From the Question,

• Force Exerted,F = 180N

• Displacement,s = 50m

• ∅ = 24°

Substituting the values,we get:

W = (180)(50)cos24

→W = 9000.cos24

→W = 9×10³.cos24

The work done in pushing the trolley is 9×10³.cos24

Answer 2

${\bold{\underline{\underline{Answer:}}}}$

${\bold{\therefore Work\:done=9\times10^{3} cos24\degree}}$

${\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about a woman pushes a lawn roller with a force of 180 Newton and the angle of 24 degree downwards from horizontal. to push a roller a horizontal distance of 50 metre.

• We have to find work done by her.

$\underline \bold{Given : } \\ \implies Force(F) = 180 \: n \\ \\ \implies Angle \: of \: force = 24 \degree \: downwards \\ \\ \implies Horizontal \: distance = 50 \: m \\ \\ \underline \bold{To \: Find : } \\ \implies Work\:done = ?$

• According to given question :

$\bold{In \: Horizontal \: direction : } \\ \\ \bold{By \: formula \: of \: work \: done : } \\ \implies Work \: done = Force \times Displacement \times \cos\theta\\ \\ \bold{\implies W = F \: s \: cos \theta} \\ \\ \implies W= 180 \times 50 \times cos 24 \degree \\ \\ \implies W = 9000 \times cos 24 \degree \\ \\ \bold{\implies W = 9000 \: cos 24 \degree} \\ \\ \bold{\therefore Work \: done \: for \: moving \: trolley }\\ \bold {\: \: \: \: is \: 9 \times {10 }^{3} cos 24 \degree}$