A woman reduces her weight in the ratio 7:5 . What does her weight become if originally it was 91 kg
Answers
Answered by
157
Let the weight after reduction be x.
∴ 91/x = 7/5
⇒ x = 91/7 × 5 = 65
Her weight becomes 65 kg if originally it was 91 kg.
∴ 91/x = 7/5
⇒ x = 91/7 × 5 = 65
Her weight becomes 65 kg if originally it was 91 kg.
Anurag19:
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Answered by
68
Let her present weight be y.
7:5 :: 91:y
So,
91*5 = 7y
455 = 7y
y = 455/7
∴y = 65
7:5 :: 91:y
So,
91*5 = 7y
455 = 7y
y = 455/7
∴y = 65
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