Math, asked by Pabitra3, 1 year ago

a woman reduces her weight in the ratio 7:5.What does her weight become if originally it was 91 kg

Answers

Answered by Anu172000
6
The answer is 65kg.We took the reduced weight to be x.Then,as per the ques. 7/5=91/x.By crisscrossing we will get x=91*5/7.=65
Answered by DiyanaN
1
Hy friend!

Nice question

Here your answer :
____________________________


Given ration of previous weght:present weight =7:5

Let previous weight =7x

present weight=5x

Given 7x=91

Let us equate it

x=91/7=13

Thus present weight =5x

=5*13

=65 kg
_____
_____

HOPE IT HELPS
Similar questions