Question

A woman's son is 2 years older
than her daughter. Her age is
3 times the sum of the ages
of her children. After 5 years
she will be 47 years old. Find
the present ages of the children​

Answer 1

Solution:-

• The present age of the woman is 47 - 5 = 42.

• Since the woman's age is 3 times the sum of the ages of the children,

• This sum is 42/3 = 14.

• So for children ages you have two equations:

=> s + d = 14,

=> s - d = 2.

• Every time when you see two equations like these, add them.

• You will get

=> 2s = 14 + 2,

=> 2s = 16,

=> s = 16/2 = 8.

Thus son is 8 years now.

The daughter is 8 - 2 = 6 years.

i hope it helps you.