Math, asked by leezac7700, 1 month ago

A woman’s store sells the following categories of clothing or the following prices : Blouse :GH 14 Skirt:GH 16 Dress:GH 25 Pantyhose:GH 2 pair for GH3 Socks :GH 7 A lady goes to the store on a day when the store has 20% off sale on all skirts.If Yaa buys 2 skirts,1 dress ,and 4 pairs of pantyhose,How much money does lady have to pay ?

Answers

Answered by RvChaudharY50
3

Given :- Price of clothing are :-

  • Blouse : GH 14
  • Skirt : GH 16
  • Dress :GH 25
  • Pantyhose:GH 2 pair for GH3 .
  • pair of Socks : GH 7

Items woman buy at 20% off on skirts :-

  • 2 skirts, 1 dress and 4 pairs of pantyhose .

To Find :-

  • How much money does lady have to pay ?

Solution :-

since discount of 20% is on skirts only, she has to pay full amount for dress and pantyhose .

so,

→ MP of 1 dress = GH 25 = Amount she pays for 1 dress .

now,

→ MP of a pair of pantyhose = GH3

→ MP of 4 pair of pantyhose = 4 * 3 = GH 12 = Amount she pays for 4 pair of pantyhose .

now,

→ MP of 1 skirt = GH 16

→ Discount = 20%

→ SP of 1 skirt = (16 * 80)/100 = GH 12.8

so,

→ SP of 2 skirts = 2 * 12.8 = GH 25.6 = Amount she pays for 2 skirts .

therefore,

→ Total amount lady has to pay = GH 25 + GH 12 + GH 25.6 = GH 62.6 (Ans.)

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Answered by akolbilak
0

Answer:

Step-by-step explanation:

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