A woman saves Rs 300 in one month. In what time will she saves Rs 2000?(1month =30 days)
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Answered by
4
if a woman saves 300 rupees in one month then it save 300/30=10 rupees per day.
To calculate the time taken by the women to save 2000 rupees we devide total money by the money saved in one day.
Tolal days= 2000 /10
Total days=200
women takes 6 months and 20 days to save 2000 rupees if she saves 300 rupees per month.
To calculate the time taken by the women to save 2000 rupees we devide total money by the money saved in one day.
Tolal days= 2000 /10
Total days=200
women takes 6 months and 20 days to save 2000 rupees if she saves 300 rupees per month.
Answered by
0
Hey mate !!
Here's your answer !!
We can solve this sum using Arithmetic Progressions.
Given :
a = 300
aₓ = 2000
d = Rs 300
To find :
x = ?
Proof :
aₓ = a + ( x - 1 ) * d
= 2000 = 300 + ( x - 1 ) 300
= 2000 - 300 = ( x - 1 ) 300
= 1700 = ( x - 1 ) 300
=> 1700 / 300 = ( x - 1 )
= 17 / 3 = ( x - 1 )
= 5.6 = ( x - 1 )
=> 5.6 + 1 = x
=> x = 6.6 months.
Hence it would take 6.6 months to save Rs 2000.
Hope my answer helped !!
Cheers !!
Here's your answer !!
We can solve this sum using Arithmetic Progressions.
Given :
a = 300
aₓ = 2000
d = Rs 300
To find :
x = ?
Proof :
aₓ = a + ( x - 1 ) * d
= 2000 = 300 + ( x - 1 ) 300
= 2000 - 300 = ( x - 1 ) 300
= 1700 = ( x - 1 ) 300
=> 1700 / 300 = ( x - 1 )
= 17 / 3 = ( x - 1 )
= 5.6 = ( x - 1 )
=> 5.6 + 1 = x
=> x = 6.6 months.
Hence it would take 6.6 months to save Rs 2000.
Hope my answer helped !!
Cheers !!
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