Math, asked by Jaisinghal5733, 26 days ago

A woman spent 1/3 of her money at the market, and 1/4 at the chemist, 1/6 at the electrical shop and has #1.85 left. How much money had she at first?

Answers

Answered by Nivlem
1

Answer:

Started with x

x - (1/3) x - (1/4) x - (1/6) x = 555

(12/12 - 4/12 - 3/12 -2/12)x = 555

(3/12)x = 555

(1/4 )x = 555

x = 4 * 555

I think this is the correct answer. Hope this is helpful.

Answered by NainaRamroop
0

The woman had #7.4 at first.

Given:

A woman spent 1/3 of her money at the market, and 1/4 at the chemist, 1/6 at the electrical shop and has #1.85 left.

To Find:

How much money does the woman have first?

Solution:

Consider the money the woman had at first (or) the total money as 'x'.

Now, if you deduct all the money she spent it should be 1.85.

The money she spent at the market = 1/3 of x = x/3

The money she spent at the chemist = 1/4 of x = x/4

The money she spent at the electrical shop = 1/6 of x = x/6

Now add all the expenditure and subtract it from x and equal it to 1.85

x - [ x/3 + x/4 + x/6 ] = 1.85

x - [ (4x+3x+2x) /12] = 1.85   Here take the LCM of the fractions.

             x - [ 9x/12 ] = 1.85

         ( 12x - 9x )/12 = 1.85   Again take the LCM

                    3x / 12 = 1.85

                           3x = 1.85 * 12

                           3x = 22.2

                             x = 22.2 / 3

                             x = 7.4

Therefore, the woman had #7.4 with her at first

#SPJ2

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