Question

a woman standing on the edge of a cliff throws a ball straight up with a speed of 8 kmh-1 and then throws another ball straight down with speed of 8 kmh-1 from same position. what is the ratio of speeds with which the ball hit the ground​

Answer 1

Answer:

Find the ratio of speeds, the stones would have attained when they hit the ... up with initial speed u and then throws another stone straight down with same initial ... So, when the man throws the ball with speed u, it will return to him with the same ... Hence the ratio is 1:1 ... After 8 seconds, a stone is released from the balloon.

Explanation:

Answer 2

Answer:

The required ratio will be 1 : 1

Explanation:

here, the speed of the ball (which is the magnitude of the velocity) is equal to the height.

hence, when the woman throws the ball from the cliff (suppose with an initial velocity "u") then it will return to the woman at the same speed = u.

Therefore, v = u + at

where, a = acceleration

t = time

v = final velocity

u = initial velocity

So, final velocity is zero

or, 0 = u - gt

or, u = gt (downward direction)

for upward direction,

v = 0 - gt

or. v = -gt  (negative sign is due to the downward direction)

Now, we see that both the initial and final velocities are same,

So. |v| = |u| (magnitude of the velocities)

Hence the required ratio will be 1 : 1

According to the question, v = u = 8 km/h

Therefore, the required ratio will be 1 : 1

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