Math, asked by kriti200348, 1 year ago

A woman takes up all job of 8000 par month with A monthly increment of 100 ....what will she earn over a period of 10 yrs????? Pls answer it..... It's urgent..... ND remember rupees 100 r monthly increment....

Answers

Answered by givemewisdom
0

Her earning over a period of 10 years = 8000+ 8100+8200 +.......+(8000+(118*100)) + (8000+(119*100))

= 8000+8100+8200+....+19800+19900

= 120*(8000+19900)/(2)

= 60*27900= 16,74,000

Answered by Rameshbishnoi
0

women salary per month= 8000

increment he got per month = 100

how many she earn over the period of 10 years

so 12 months = 1 year

=12month x10 years

=120 month

Now total money she earn =8000+100=8100

=8100x120=97,200

ANS= The women earn Rs97200 in the period of 10 years

if the answer is right plz mark as brainliest


Rameshbishnoi: soryy the answer is 97200p
Rameshbishnoi: 972000
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