A woman throws an object of mass 500 g with a speed of 25 m/s. (i) what is the impulse imparted to the object? (ii) if the object hits a wall and rebounds with half the original speed, what is the change in momentum of the object?
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Mass of the object (m) = 500g = 0.5 kg
Speed of the object (v) = 25 m/s
(i) Impulse imparted to the object = Change in the momentum = mv-mu
= m(v-u)
= 0.5(25-0) = 12.5 N-s
(ii) Velocity of the object after rebounding = -25/2 m/s
v’ = -12.5 m/s
Change in momentum = m(v’ - v)
= 0.5 (-12.5 -25)
= -18.75 N-s
Speed of the object (v) = 25 m/s
(i) Impulse imparted to the object = Change in the momentum = mv-mu
= m(v-u)
= 0.5(25-0) = 12.5 N-s
(ii) Velocity of the object after rebounding = -25/2 m/s
v’ = -12.5 m/s
Change in momentum = m(v’ - v)
= 0.5 (-12.5 -25)
= -18.75 N-s
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