Question

A woman travels a distance of 1 meter towards north then 2 meter towards east and finally 3 meter towards south.Find displacement.

Answer 1

Well the answer is quite easy

*The displacement is 2 meters*

Answer 2

Given :-

• CD = 2 m

• DE = 2 m

To find :-

• Displacement (CE) = ?

Concept :-

☛ Displacement is the shortest distance between initial and Final point of moving object with particular direction.

• It is a vector quantity.
• SI unit of displacement is m.
• CGS unit of displacement is cm.
• Displacement may be positive, negative and zero.

Solution :-

$\rm\:Displacement\:(CE)=\sqrt{({CD)}^{2}+{(DE)}^{2}}$

$\rm\:Displacement\:(CE)=\sqrt{{(2m)}^{2}+{(2m)}^{2}}$

$\rm\:Displacement\:(CE)=\sqrt{{4m}^{2}+{4m}^{2}}$

$\rm\:Displacement\:(CE)=\sqrt{8{m}^{2}}$

$\rm\:Displacement\:(CE)=2\sqrt{2}\:m$

$\rm\:Displacement\:(CE)=2\times{1.414}$

$\rm\:Displacement\:(CE)=2.828\:m$