Question

A woman travels a distance of 1m towards north then 2m towards east and finally 3m towards south .Find total distance and displacement.​

Answer 1

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total distance=1+2+3=6m

simply joining initial and.final position u get displacement path

it makes isosceles right triangle in which hypotenuse is displacement.

2^2+2^2=displacement^2

displacement=root8=2root2=2×1.414=2.828m

Answer 2

ANSWER:

• Total distance = 6 m

• Total displacement = 2√2 m

☞GIVEN:

• A woman travels a distance of 1 m towards north
• 2 m towards east
• 3 m towards south

☞TO FIND:

Total distance

Total displacement

☞EXPLANATION:

→DISTANCE:

Distance is the actual length or total length traversed by a body.

It is a scalar as it has only magnitude but no specific direction.

Total distance travelled = 1 m + 2 m + 3 m = 6 m

→DISPLACEMENT:

Displacement is the shortest distance travelled by the body.

It is a vector as it both only magnitude and specific direction.

Let ABCD be the path travelled by the woman

Displacement = AD

By using Pythagoras theorem

AD² = AF² + FD²

AF = BC = 2 m

FD + FC = CD = 3 m

FC = AB = 1 m

1 + FD = 3

FD = 2 m

Substitute FD = 2 m and AF = 2 m in AD² = AF² + FD²

AD² = 2² + 2²

AD² = 4 + 4

AD² = 8

AD = √8

AD = 2√2

Total Displacement travelled = 2√2 m