Question

a woman walks a certain distance in 84 min she covers two thirds of it at 4km/h and the rest at 5km/h find total distance covered

Answer 1

Step-by-step explanation:

x km in 84 minutes = 7/2 hr

2/3 of x at 4km/h

x/3 at 5km/h

average speed of the total journey = 4+5/2=4.5km/h

speed =distance /time

4.5 = x/3.5

x=4.5*3.5

x=15.75km

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Answer 2

Answer:

The total distance is 6 km.

Step-by-step explanation:

Let the total distace covered by her =X

=> She covered 2X/3 with the speed

4km/h

=> The remaining distance

= X - 2X/3 = (3X - 2X) /3 = X/3

Thus she covered the distance X/3 with 5km/h

Now as we know that .:

speed = distance / time

=> speed × time = distance

=> In first case 4t = 2X/3

=> t1 = 2X/12

or t1 = X/6

Similarly the second time (t2) can also be determined from the relation as .:

=> speed × time = distance

=> 5 × t = X/3

=> t2 = X/15

But we know that total time = 84 min

which equals to 1.4 hour

=> t1 + t2 = 1.4 h

$\frac{x}{6} + \frac{x}{15} = 1.4$

$\frac{5x \: + \: 2x}{30} = 1.4$

=> 7X/30 = 1.4

=> X = (1.4 × 30)/7

=> X = 0.2 × 30

=> X = 6 km