Question

A woman walks a certain distance in 84 min. She covers two thirds of it at 4 km/h and the rest at 5 km/h. Find the total distance she covered​

Answer 1

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Given women walk a certain distance in 84 minutes in the first two-thirds of the time she walked at 4 km ph

So distance covered in 1st two-third is 

x = 4kmph × 2/3 × 84min

=4×2/3×84/60hr

x = 3.733 km

So remaining distance is

y = 5×1/3×84/60

    =2.333 km

∴  Total distance = x+y = 6.067 km