Question

a woman weighing 50kgf stands on a weighing machine placed in a lift . what will be the reading of machine when lift is 1) moving upwards with uniform velocity of 5m/s and 2) moving downwards with a uniform acceleration of 1m/s^2 ? take g=10

Answer 1

Heya.......!!!

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As we know that Weight ( W ) = Mg .

Here this is a case of moving lift . Two cases are described in your question :-

1 ) When the lift upwards with an uniform velocity of 5 m/s it's Acceleration ( a ) will be 0 .

=> W = m( g + a ) .

here a = 0 ,, So his apparent weight will be equal to his real weight that is reading in the machine will be = W = Mg = 50 × 10 =500 N .


2.) The lift is going downwards with an acceleration of 1 m/s^2 .

in this case his Apparent Weight will be :-
=> W = M ( g - a ) .

here a = 1 m/s^2 .

=> W = 50( 10−1 ) = 450N .



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Answer 2

Answer:

Refer to the attachment for your answer