Biology, asked by Rajarao2227, 1 year ago

A woman with two genes for haemophillia and one gene for colourblindness on one of the X chromosomes marries a normal man. How will the progeny be [CBSE PMT 1998]
A) All sons and daughters haemophillic and colourblind
B) Haemophillic and colourblind daughters
C) 50% haemophillic colourblind sons and 50% normal sons
D) 50% haemophillic daughters and 50% colourblind daughters

Answers

Answered by Deepaksingh111
1
D) 50% haemophillic daughters and 50% colourblind daughters
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