Question

A women has a certain number of mangoes of which 13% are rotten.She gives 75% of the remainder in charity and then has 261 left.How many had she at first?

Answer 1

Let the total number of mangoes be x
13 % are rotten = 13 × x/100 = 0.13x
Remaining mangoes = x - 0.13x = 0.87x
75 % 0f remaining mangoes given in charity = 75 × 0.87x/100
= 0.6525x
Therefore we know that,
total number of mangoes = 13 % are rotten + 75 % of the remaining given in charity + number of mangoes left
⇒ x = 0.13x + 0.6525x + 261
⇒ x = 0.7825x + 261
⇒ x - 0.7825x = 261
⇒ 0.2175x = 261
⇒ x = 261/0.2175
total number of mangoes = 1200  Answer

Answer 2

Answer:

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Step-by-step explanation:

Let the total number of mangoes be x

13 % are rotten = 13 × x/100 = 0.13x

Remaining mangoes = x - 0.13x = 0.87x

75 % 0f remaining mangoes given in charity = 75 × 0.87x/100

= 0.6525x

Therefore we know that,

total number of mangoes = 13 % are rotten + 75 % of the remaining given in charity + number of mangoes left

⇒ x = 0.13x + 0.6525x + 261

⇒ x = 0.7825x + 261

⇒ x - 0.7825x = 261

⇒ 0.2175x = 261

⇒ x = 261/0.2175

total number of mangoes = 1200 Answer