Math, asked by razsingarwaniman, 1 year ago

A women is 5 years younger then her husband and 3 times elder than her daughter if the daughter attain age of 21 years after 6 years what would be the present age of father

Answers

Answered by VatsalSatija
2
Let fathers present age be X
let mothers present age be Y
let daughter present age be Z

Mother is 5 years younger that father
=> x = y+5

Mother is 3 times older than daughter
=> 3z = Y

After 6 years daughter age will be 21
Z + 6 = 21
Present age of daughter
= 21-6 = 15 years
Z = 15

Mother is 3 times older than daughter
Y = 3z
Y = 3(15)
Y =45 years
Mother age = 45 yrs

Father is 5 years older than mother
Father age= 45+5 = 50 years old
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