Question

a women is 7 times as old as her son after 5 years she will be 4 times as old as her son what are the present age of the mother and son​

Answer 1

Answer:

let's present age of son be X year

A woman present age is 7 time as older than son women present age=7×X=(7X) year

after the five years

women's age

➪4(X+5)

➪4(X+5)=7x+5

➪4x+20=7X-4x

➪20-5=7x-4x

➪15=3x

➪X=5

present age of son is X=5 year

mother's➪7x=7×5

➪35 years

Answer 2

Given :-

• A women is 7 times as old as her son.
• After 5 years she will be 4 times as old as her son.

To find :-

• Present age of the mother and son?

Solution :-

Let Present age of son be x years.

Then, Present age of mother will be 7x years.

Now,

★ According to the question:

• After 5 years mother will be 4 times as old as her son.

Their ages after 5 years,

• Age of son = (x + 5) years
• Age of mother = (7x + 5) years

Therefore,

⇒ (7x + 5) = 4(x + 5)

⇒ 7x + 5 = 4x + 20

⇒ 7x - 4x = 20 - 5

⇒ 3x = 15

⇒ x = 15/3

⇒ x = 5

Therefore,

• Present age of son, x = 5 years
• Present age of mother, 7x = 35 years

∴ Hence, Present age of mother and her son is 35 years and 5 years respectively.