Question

A women is six times as old as her son. Two years ago , the product of their ages was 84. Find the present ages.

{SOLVE STEP WISE}
(the person who gave the answer first will be marked as most brilliant.)​

Answer 1

let the women age be x

son age be y

6(x+y)+2-x=84. ........1

6x+6y+2-x=84

5x+6y=82

x+y=82/5/6

x+y=82*6/5

x+y=492/5

simplify this and x=492/5-y

and put this in 1 equation

u got your answer

Answer 2

Answer:

Step-by-step explanation:

Let the son's age be a

Therefore,her mother's age = 6a

Son's age two years ago = a-2

Mother's age 6years ago = 6a-2

ACC to questions

a-2*6a-2=84

a*6a-2+2=84(cut -2and+2)

a*6a=84

a*a=84/62

2a =14

a=14/2

a=7

There present ages:

Son's age= a+2=7+2=9

Mother's age = 6a +2= 42+2=44 years