Question

A women is wearing sharp hill shose or if the mass of this women 50kg and the area of 1 hill is 1cm². Calculate the pressure exerted on the ground when the women stands on just one hill

Answer 1

mass of woman = 50kg

weight = mg = 50 × 9.8 = 490 N

So force exerted by woman = 490N

area of heel = 1 cm^2 = 0.0001 m^2

Pressure =Force/area = 490 / 0.0001 = 4.9×10^6 Pa = 4.9 MPa

Pressure exerted on ground is 4.9MPa

Answer 2

$\bf\huge\boxed{\boxed{\boxed{Cybary\:Radhe\:Radhe}}}$

Mass of woman = 50kg

Weight = mg

= 50 × 9.8

= 490 N

HENCE :-

Force exerted by woman = 490N

Area of heel = 1 cm^2

= 0.0001 m^2

Pressure = $\bf\huge\frac{Force}{Area}$

= $\bf\huge\frac{490}{0.0001}$

= 4.9×10^6 Pa

= 4.9 MPa

Pressure exerted on ground

$\bf\huge\boxed{\boxed{4.9\:Mpa}}}$

$\bf\huge\boxed{\boxed{\boxed{Radhe\:Radhe}}}$