Question

A women reduces her weight in the ratio 7:5. What does her weight become if originally it was 91 kg

Answer 1

Answer:

$\large{\underline{\boxed{\sf Reduced\: Weight = 65 \: kg}}}$

Step-by-step explanation:

It is given that, a women reduces her weight in the ratio 7:5.

Let the original weight of women be 7x and the reduced weight of women be 5x respectively.

According to the question ;

Original weight of women = 91 kg

∴ 7x = 91

⇒ x = $\dfrac{91}{7}$

⇒ x = 13

Now, the reduced weight of women is 5x. So,

5x = 5 * 13

= 65 kg

Hence, the reduced weight of women is 65 kg.

Answer 2

Answer:

LET WEIGHT AFTER REDUCING =X

ORIGINAL WEIGHT = 91 KG

SO, RATIO = 91:X

AND GIVEN RATIO = 7:5

= >    91/X = 7/5

=>      455 = 7 X             [ BY CROSS MULTIPLICATION]

=>       X = 455/7

=>        X = 65

WEIGHT AFTER REDUCING = X = 65 KG