Question

A women's son is 2 yrs older than her daughter. Her age is three times the sum of the ages of her children. After 5yrs she will be 47 yrs old. Find the present ages of the children

Answer 1

Daughter =6
Son =8
$3(x + x + 2) + 5 = 47 \\ 6x + 11 = 47 \\ 6x = 36 \\ x = 6 \\ x + 2 = 8$
Let age if daughter = x
Let age of Son = x+2

Answer 2

Solution:-

• The present age of the woman is 47 - 5 = 42.

• Since the woman's age is 3 times the sum of the ages of the children,

• This sum is 42/3 = 14.

• So for children ages you have two equations:

=> s + d = 14,

=> s - d = 2.

• Every time when you see two equations like these, add them.

• You will get

=> 2s = 14 + 2,

=> 2s = 16,

=> s = 16/2 = 8.

Thus son is 8 years now.

The daughter is 8 - 2 = 6 years.

i hope it helps you.