Question

A women self help group (DWACRA) is supplied a rectangular solid (cuboid shape) of wax with diameters 66 cm., 42 cm., 21 cm., to prepare cylindrical candles each 4.2 cm. in diameter and 2.8 cm. of height. Find the number of candles.

Answer 1

The volume of the wax is :

66 × 42 × 21 = 58212 cm³

Volume of one candle :

22/7 × 2.1² × 2.8 = 38.808

Number of candles will be :

58212 / 38.808 = 1500 candles.

Answer 2

Answer:

1535 candles can be formed .

Step-by-step explanation:

Length of rectangular solid = 66 cm

Breadth of rectangular solid = 42 cm

Height of rectangular solid = 21 cm

Volume of of rectangular solid =$Length \times Breadth \times Height$

                                                   =$66 \times 43 \times 21$

                                                  =$59598 cm ^3$

Diameter of cylindrical candle = 4.2 cm

Radius of cylindrical candle = $\frac{4.2}{2} =2.1 cm$

Height of cylindrical candle = 2.8 cm

Volume of cylindrical candle = $\pi r^2 h = \frac{22}{7} \times 2.1^2 \times 2.8=38.808 cm^3$

No. of candles can be formed from rectangular solid = $\frac{59598}{38.808}=1535.714$

Hence 1535 candles can be formed .