Math, asked by uhmad, 8 months ago

A women sells to the first customer half her stock of apples and half an apple , to the second customer she sells half her remaining stock and half an apple , and so on to the third and to the fourth customer. She finds that she has now 15 apples left . How many apples did she have before she started selling?​

Answers

Answered by Anonymous
2

Answer:

\huge\underline\bold {Answer:}

Suppose she had x apples in the beginning.

Sold to the first customer

 \frac{x}{2}  +  \frac{1}{2}  =  \frac{x + 1}{2} \\

Remaining stock

 = x -  \frac{x + 1}{2}  =  \frac{2x - x - 1}{2}  \\  =  \frac{x - 1}{2}

Sold to the second customer

 =  \frac{1}{2}  \times  \frac{x - 1}{2}  +  \frac{1}{2}  \\  =  \frac{x - 1}{4}  +  \frac{1}{2}

 =  \frac{x - 1 + 2}{4}  =  \frac{x + 1}{4}

Remaining stock

 = ( \frac{x - 1}{2})  - ( \frac{x + 1}{4} ) \\  =  \frac{2x - 2 -  x - 1}{4}  \\  =   \frac{x - 3}{4}

Sold to the third customer

 =  \frac{1}{2}  \times  \frac{x - 3}{4}  +  \frac{1}{2}  \\  =  \frac{x - 3 + 4}{8}  \\  =  \frac{x + 1}{8}

Remaining stock

 = ( \frac{x - 3}{4} ) - ( \frac{x + 1}{8} ) \\  =  \frac{2x - 6 - x - 1}{8}  =  \frac{x - 7}{8}

Sold to the fourth customer

 =  \frac{1}{2}  \times  \frac{x - 7}{16}  +  \frac{1}{2}  \\  =  \frac{x - 7}{16}  +  \frac{1}{2}  \\  =  \frac{x - 7 + 8}{16}  \\  =  \frac{x + 1}{16}

Therefore,

x -  (  \frac{x + 1}{2}  +  \frac{x + 1}{4}  +  \frac{x + 1}{8}  +  \frac{x + 1}{16} ) \\  = 15

 =  > x - ( \frac{8x + 8 + 4x + 4 + 2x + 2 + x + 1}{16} ) \\  = 15

 =  > x - ( \frac{15x + 15}{16} ) = 15 \\  =  >  \frac{16 x - 15x - 15}{16}  \\  = 15 \\  =  >x  - 15 = 16 \times 15 = 240 \\  =  > x = 240 + 15 = 255.

Therefore, she had 225 apples before she started selling.

Answered by dont96
2

Step-by-step explanation:

In the given question the woman is selling the apples through 2 different processes to different customers.

Do the reverse of what woman is doing & start from 15 apples.

Step 1: Reverse of “Giving away(selling) half an apple and half of her remaining stock” : Double the no. of apples & add half apple.

15 x 2 + .5 = 30.5

30.5 is the no. of apples she had before selling to the 4th customer.

Step 2: Reverse of “Giving away half her stock of apples and half an apple” : Add half apple & double the stock.

(30.5 + .5) x 2 = 62

62 is the no. of apples she had before selling to the 3rd customer.

Step 3: Repeat step 1

62 x 2 + .5 = 124.5

124.5 is the no. of apples she had before selling to the 2nd customer.

Step 4: Repeat step 2

(124.5+.5) x 2 = 250

250 is the no. of apples she had before selling to the 1st customer.

So the answer is 250

Or through options

C: 250

If she begins with 250 apples

Apples Left

250 ------> 124.5 : After giving 125 and then .5 apple

124.5------> 62 : After giving .5 and then 124/2 =62 apples

62 ------> 30.5 : After giving 125 and then .5 apple

30.5--------> 15 : After giving .5 and then 15 apples

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