A women sells to the first customer half her stock of apples and half an apple , to the second customer she sells half her remaining stock and half an apple , and so on to the third and to the fourth customer. She finds that she has now 15 apples left . How many apples did she have before she started selling?
Answers
Answer:
Suppose she had x apples in the beginning.
Sold to the first customer
Remaining stock
Sold to the second customer
Remaining stock
Sold to the third customer
Remaining stock
Sold to the fourth customer
Therefore,
Therefore, she had 225 apples before she started selling.
Step-by-step explanation:
In the given question the woman is selling the apples through 2 different processes to different customers.
Do the reverse of what woman is doing & start from 15 apples.
Step 1: Reverse of “Giving away(selling) half an apple and half of her remaining stock” : Double the no. of apples & add half apple.
15 x 2 + .5 = 30.5
30.5 is the no. of apples she had before selling to the 4th customer.
Step 2: Reverse of “Giving away half her stock of apples and half an apple” : Add half apple & double the stock.
(30.5 + .5) x 2 = 62
62 is the no. of apples she had before selling to the 3rd customer.
Step 3: Repeat step 1
62 x 2 + .5 = 124.5
124.5 is the no. of apples she had before selling to the 2nd customer.
Step 4: Repeat step 2
(124.5+.5) x 2 = 250
250 is the no. of apples she had before selling to the 1st customer.
So the answer is 250
Or through options
C: 250
If she begins with 250 apples
Apples Left
250 ------> 124.5 : After giving 125 and then .5 apple
124.5------> 62 : After giving .5 and then 124/2 =62 apples
62 ------> 30.5 : After giving 125 and then .5 apple
30.5--------> 15 : After giving .5 and then 15 apples