Question

A wood block of mass 3kg is resting on the surface of a rough incline surface. Angle of inclination of the surface

is as shown in fig.

(i) Name the forces 1,2 and 3

(ii) If the coefficient of static friction is 0.2. Calculate the value of all the three forces (Take g = 10m/s2
) ???​

Answer 1

Explanation:

HEY MATE .........

$if \: thetha = 30 \: and \: \\ \\ u = 0.2 \: \\ \\ then \: it \: is \: clear \: that \: angle \: \\ \\ thetha \: is \: greater \: \\ \\ than \: the \: angle \: of \: repose \: \\ \\ \\ hence \: force \: of \: friction \: \\ \\ has \: its \: maximum \: value \: \\ \\ = umgcos \: thetha \\ \\ \\ force \: 1 = \: mg = 3 \times 10 \\ \\ = 30 |n| \\ \\ 2 \\ \\ = umg \: cos thetha \\ \\ = 0.2 \times 3 \times 10 \times \: cos \: thetha \\ \\ = 5.2 |n| \\ \\ and \: force \: 3 \\ \\ = mgcos \: thetha \: = 26.0 |n|$

Answer 2

ifthetha=30and

u=0.2

thenitisclearthatangle

thethaisgreater

thantheangleofrepose

henceforceoffriction

hasitsmaximumvalue

=umgcosthetha

force1=mg=3×10

=30∣n∣

2

=umgcosthetha

=0.2×3×10×costhetha

=5.2∣n∣

andforce3

=mgcosthetha=26.0∣n∣