Question

a wooden archeological specimen contains 15% of the original C-14. using the half life of 5730 years. determine the approx. age of the specimen

Answer 1

Given info : a wooden archeological specimen contains 15% of the original C-14. using the half life of 5730 years.

To find : the approximate age of the specimen is ...

solution : half life of any radioactive decay is given by, T = ln2/k , where k is decay constant.

here T = 5730 yrs

so, k = ln2/5730 yr¯¹

a/c to question, a wooden archeological specimen contains 15 % of the C - 14.

if N₀ = 100, then N = 15 % of 100 = 15

now using formula, t = 1/k ln[N₀/N]

= 1/(ln2/5730) × ln[100/15]

= ln(20/3) × 5730/ln2

= 15,682.8129 yrs

≈ 15,683 yrs

Therefore the approximate age of the specimen is 15,683 yrs.

Answer 2

Answer:

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