Question

a wooden article was made by scooping out a hemisphere from one end of a cylinder and a cone from other end as shown in the fig. if the hight of cone is 24cm. find the value of wooden article.​

Answer 1

Step-by-step explanation:

• Volume of article=volume of cylinder-(volume of cone+volume of hemisphere)
• Volume of article=volume of cylinder-(volume of cone+volume of hemisphere)Volume of cylinder=>`pir^2h=22/7xx7xx7xx40=6160(cm)^2`
• Volume of article=volume of cylinder-(volume of cone+volume of hemisphere)Volume of cylinder=>`pir^2h=22/7xx7xx7xx40=6160(cm)^2`volume of hemisphere=`2/3pir^3=2/3xx22/7xx7xx7xx7=718.6(cm)^3`
• Volume of article=volume of cylinder-(volume of cone+volume of hemisphere)Volume of cylinder=>`pir^2h=22/7xx7xx7xx40=6160(cm)^2`volume of hemisphere=`2/3pir^3=2/3xx22/7xx7xx7xx7=718.6(cm)^3`volume of cone=`1/3pir^2h=1/3xx22/7xx7xx7xx24=1232(cm)^3`
• Volume of article=volume of cylinder-(volume of cone+volume of hemisphere)Volume of cylinder=>`pir^2h=22/7xx7xx7xx40=6160(cm)^2`volume of hemisphere=`2/3pir^3=2/3xx22/7xx7xx7xx7=718.6(cm)^3`volume of cone=`1/3pir^2h=1/3xx22/7xx7xx7xx24=1232(cm)^3`Volume of article=`(6160-718.6-1232)=4209.4(cm)^3`
• Volume of article=volume of cylinder-(volume of cone+volume of hemisphere)Volume of cylinder=>`pir^2h=22/7xx7xx7xx40=6160(cm)^2`volume of hemisphere=`2/3pir^3=2/3xx22/7xx7xx7xx7=718.6(cm)^3`volume of cone=`1/3pir^2h=1/3xx22/7xx7xx7xx24=1232(cm)^3`Volume of article=`(6160-718.6-1232)=4209.4(cm)^3`Total surface area=Curved surface area of (cone+cylinder+hemisphere)`pirl+2pirh+2pir^2=>pi(7xx25+2xx7xx40+2xx49)`
• Volume of article=volume of cylinder-(volume of cone+volume of hemisphere)Volume of cylinder=>`pir^2h=22/7xx7xx7xx40=6160(cm)^2`volume of hemisphere=`2/3pir^3=2/3xx22/7xx7xx7xx7=718.6(cm)^3`volume of cone=`1/3pir^2h=1/3xx22/7xx7xx7xx24=1232(cm)^3`Volume of article=`(6160-718.6-1232)=4209.4(cm)^3`Total surface area=Curved surface area of (cone+cylinder+hemisphere)`pirl+2pirh+2pir^2=>pi(7xx25+2xx7xx40+2xx49)`=>Answer=`2618(cm)^2`