A wooden article was made by scooping out a hemisphere from each end of a solid cylinder. if the height of cylinder is 10 CM and its base is of radius 3.5 CM. find the total surface area of the article
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Answered by
7
T.S.A of hemisphere = 2/3 pi r cube
T.S.A OF CYLINDER = 2 PI R (h+r)
T.S.A OF CYLINDER = 2 *22/7*3.5(10+3.5)
= 44/7 (35+12.25)
=44/7 (47.25) CM CUBE
Answered by
24
Given
Height of the cylinder = 10 cm
Radius of the base of the cylinder = 3·5 cm
Total surface area of article
= C.S.A. of cylinder + 2 × Area of hemisphere
= 2πrh + 2 × 2π ²
= 2π(h + 2r)
= 2 × 22/7 × 3·5 (10 + 2 × 3·5)
= 2 × 22 × 0·5 (10 + 7)
= 44 × 0·5 × 17
= 748 × 0·5
Total surface area of article
= 374 cm²
Height of the cylinder = 10 cm
Radius of the base of the cylinder = 3·5 cm
Total surface area of article
= C.S.A. of cylinder + 2 × Area of hemisphere
= 2πrh + 2 × 2π ²
= 2π(h + 2r)
= 2 × 22/7 × 3·5 (10 + 2 × 3·5)
= 2 × 22 × 0·5 (10 + 7)
= 44 × 0·5 × 17
= 748 × 0·5
Total surface area of article
= 374 cm²
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