a wooden ball of mass 0.5kg moving with a velocity of 10 m/s directly hits another ball of mass 4.5kg at rest. After the impact ,it sticks to the heavier ball.Then the velocity of combined mass is
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Answer: 1 m/s
Explanation:
m1u1 + m2u2 = (m1+m2)Vf
0.5*10 + 4.5*0 = (0.5+4.5)Vf
5 = 5Vf
5 5
Vf = 1 m/s
robinpaudel:
two particles having masses 1 gm and 4 gm are moving with equal kinetic energies. The ratio of their linear momenta is:
can you solve it ?
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