Question

A wooden bloc of mass 6kg is pulled across rough surface by a 50N force agnist a friction force F. the acceleration of block is 6m/s^2 then the value of friction force F is​

Answer 1

$net \: force \: = applied \: force \: - friction \: force$
$= > F_{net} = 50 - f$
where f= friction force
a= acceleration = force /mass
applied force =50N
mass = 6kg
a= 50/6
= 25/3
and by a=
25/6 -f/6
now put the value and get the answer