Question

A wooden block exerts a force of 500 N perpendicular to the horizontal surface. If the coefficient of friction between the block and the surface is 0.45, what is magnitude of limiting friction?

Answer 1

normal reaction (R) = 500N ;
coefficient of friction (u) = 0.45
limiting friction (f) =U*R
=0.45*500
= 225N

Answer 2

$\huge\bold\pink{SOLUTION:-}$

Given,

Normal Reaction (N) = 500 N

Co-efficient of Friction (u) = 0.45

Now,

As we know that, there is a Formula to find Limiting Friction :-

Limiting Friction = u x N

Limiting Friction = (0.45 x 500) N

Limiting Friction = 225 N

Hence, the magnitude of limiting force = 225 N